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Question

Find the integral :
cosxcos(xa)dx

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Solution

cos(x)cos(xa)dx=cos(xa+a)cos(xa)dx

cos((xa)+a)cos(xa)dx=[cos(xa)×cosacos(xa)+sin(xa)×sinacos(xa)]dx

=[cos(a)+tan(xa)×sin(a)]dx

=xcos(a)+sin(a)×log(secx)+C

cos(x)cos(xa)dx=xcos(a)+sin(a)×log(secx)+C



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