Question

Find the integral: $\int \sec x(\sec x+\tan x)dx$

Answer 1

$\int \sec x(\sec x+\tan x)dx$
$=\int ({\sec }^{2}x+\sec x\tan x)dx$
$=\int {\sec }^{2}xdx+\int \left(\sec x\tan x\right)dx$
$=\tan x+\sec x+C$

Where $C$ is constant of integration