No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
ex2−4+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
ln(x2−4)+C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
ex2−42x+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Cln(x2−4)+C Given, f(x)=2xx2−4
So, to integrate the given function we use substitution method.
Let t=x2−4⇒dtdx=2x
Or, dt=2xdx
Thus, substituting this value in the given function we have, ∫2xx2−4dx=∫1tdt=lnt+C ⇒ln(x2−4)+C