Question

Find the integral of $\int \frac{2-3\sin x}{{\cos }^{2}x}dx$

Answer 1

$\int \frac{2-3\sin x}{{\cos }^{2}x}dx$

$=\int (\frac{2}{{\cos }^{2}x}-\frac{3\sin x}{{\cos }^{2}x})dx$

$=\int 2{\sec }^{2}xdx-3\int \tan x\sec xdx$

$=2\tan x-3\sec x+C$