Question

Find the integral of $\int \frac{x^3-x^2+x-1}{x-1}dx$

Answer 1

$\int \frac{x^3-x^2+x-1}{x-1}dx$
On dividing, we obtain
$=\int (x^2+1)dx$
$=\int x^{2}dx+\int 1dx$
$=\frac{x^3}{3}+x+C$