Question

Find the integral of $\int {(\sqrt{x}-\frac{1}{\sqrt{x}})}^{2}dx$

Answer 1

$\int {(\sqrt{x}-\frac{1}{\sqrt{x}})}^{2}dx$
$=\int (x+\frac{1}{x}-2)dx$
$=\int xdx+\int \frac{1}{x}dx-2\int 1.dx$
$=\frac{x^2}{2}+\log |x|-2x+C$