Question

Find the integral of $\int \sec x(\sec x+\tan x)dx$

Answer 1

$\int \sec x(\sec x+\tan x)dx$
$=\int ({\sec }^{2}x+\sec x\tan x)dx$
$=\int {\sec }^{2}xdx+\int \sec x\tan xdx$
$=\tan x+\sec x+C$