Question

Find the integral of $\int x^2(1-\frac{1}{x^2})dx$

Answer 1

$\int x^2(1-\frac{1}{x^2})dx$
$=\int (x^2-1)dx$
$=\int x^{2}dx-\int 1dx$
$=\frac{x^3}{3}-x+C$