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Question

Find the integral of the given function w.r.t x

y=13x2


A

33x

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B

23x2/3

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C

33x+c

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D

none of these

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Solution

The correct option is C

33x+c


y=13x2

The above can be written as:

y=x2/3

now Integration of above w.r.t. x = (x)2/3dx

We know xndx=xn+1n+1+c

x2/3dx=x(23+1)23+1+c

x1313+c=33x+c

I hope you remmember why 'c'

Integral also known as antiderivate of a function when differentiated gives back the same function.

Sod(33x)dx=13x2


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