CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the integrals of the functions sin3x+cos3xsin2xcos2x

Open in App
Solution

sin3x+cos3xsin2xcos2x=sin3xsin2cos2x+cos3xsin2xcos2x
=sinxcos2x+cosxsin2x
=tanxsecx+cotxcosecx
sin3x+cos3xsin2xcos2xdx=(tanxsecx+cotxcosecx)dx
=secxcosecx+C

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems on Integration
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon