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Question

Find the integrating factor for the differential equation
dydx+y2xsinx=0

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Solution


dydx+y2x=sinx

Compare it with standard form
dydx+Py=Q, where P and Q are functions of x, we get
P=12x

Integrating factor is given as,
I.F.=ePdx
I.F.=e12xdx
I.F.=ex

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