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Byju's Answer
Standard XII
Physics
Integration
Find the inte...
Question
Find the integration of
∫
e
tan
−
1
x
1
+
x
2
.
d
x
A
e
tan
−
1
x
+
C
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B
e
−
tan
−
1
x
+
C
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C
e
tan
−
1
x
2
+
C
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D
e
tan
x
+
C
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Solution
The correct option is
A
e
tan
−
1
x
+
C
Given,
∫
e
tan
−
1
x
1
+
x
2
.
d
x
Let
t
=
tan
−
1
x
⟹
d
t
=
1
1
+
x
2
.
d
x
⇒
d
x
=
(
1
+
x
2
)
.
d
t
Putting these value in above integration
∴
we have
I
=
∫
e
t
.
d
t
=
e
t
+
C
∴
I
=
e
tan
−
1
x
+
C
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0
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