Find the intensities $I_{1}$ and $I_{2}$ from each speaker at point P separately.

I_{1} = 29.9 μ W / m^{2}

I_{2} = 8.814 μ W / m^{2}

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I_{1} = 19.9 μ W / m^{2}

I_{2} = 8.814 μ W / m^{2}

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I_{1} = 32.9 μ W / m^{2}

I_{2} = 8.814 μ W / m^{2}

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I_{1} = 24.9 μ W / m^{2}

I_{2} = 8.814 μ W / m^{2}

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Solution

The correct option is B $I_{1} = 19.9 μ W / m^{2}$ , $I_{2} = 8.814 μ W / m^{2}$
Here, $I = \frac{I}{4 π r^{2}}$
Therefore, $I_{1} = \frac{1 * 10^{- 3}}{4 π (2)^{2}}$ = $19.9 μ W / m^{2}$
$I_{2} = \frac{1 * 10^{- 3}}{4 π (3)^{2}}$ = $8.8 * 10^{- 6} μ W / m^{2}$
Correct answer is B.

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Similar questions

Now what should be the correct relation between $I_{1}$ , $I_{2}$ and $I_{3}$ .

I_{1} = π / 2 \int 0 cos (sin x) d x; I_{2} = π / 2 \int 0 sin (cos x) d x

I_{3} = π / 2 \int 0 cos x d x,

90^{\circ}

M_{1}

M_{2}

I_{1} = \int_{0}^{\frac{π}{2}} c o s (π s i n^{2} x) d x, I_{2} = \int_{0}^{\frac{π}{2}} c o s (2 π s i n^{2} x) d x a n d I_{3} = \int_{0}^{\frac{π}{2}} c o s (π s i n x) d x,

I_{1} = \int_{0}^{\frac{π}{4}} x^{2008} (t a n x)^{2008} d x, I_{2} = \int_{0}^{\frac{π}{4}} x^{2009} (t a n x)^{2009} d x a n d I_{3} = \int_{0}^{\frac{π}{4}} x^{2010} (t a n x)^{2010} d x

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