Find the intercepts cut off by the line $x - 3 y + 8 = 0$ on the axes.

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Solution

$x -$ intercept:Put $y = 0$

$∴ x + 8 = 0$

$\Rightarrow x = - 8$ is the $x -$ intercept

$y -$ intercept:Put $x = 0$

$∴ - 3 y + 8 = 0$

$\Rightarrow y = \frac{- 8}{- 3} = \frac{8}{3}$ is the $y -$ intercept.

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a

and

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the intercepts cut off on the coordinate axes by the line

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Find the intercepts cut off by the line x−3y+8=0 on the axes.

x−intercept:Put y=0∴x+8=0⇒x=−8 is the x−intercepty−intercept:Put x=0∴−3y+8=0⇒y=−8−3=83 is the y−intercept.

Find the intercepts cut off by the line $x - 3 y + 8 = 0$ on the axes.

$x -$ intercept:Put $y = 0$

$∴ x + 8 = 0$

$\Rightarrow x = - 8$ is the $x -$ intercept

$y -$ intercept:Put $x = 0$

$∴ - 3 y + 8 = 0$

$\Rightarrow y = \frac{- 8}{- 3} = \frac{8}{3}$ is the $y -$ intercept.