Question

Find the intercepts cut off by the plane

Answer 1

The equation of plane in intercept form is,

x a + y b + z c =1(1)

Here,

a is the intercept of the plane with the x axis.

b is the intercept of the plane with the y axis.

c is the intercept of the plane with the z axis.

The given equation of plane is,

2x+y−z=5

Divide both sides of the equation by 5.

2x 5 + y 5 − z 5 =1 x ( 5 2 ) + y 5 + z ( −5 ) =1 (2)

Compare equations (1) and (2).

a= 5 2

b=5

c=−5

The intercept of the plane with x axisis 5 2 .

The intercept of the plane with y axisis 5.

The intercept of the plane with z axisis −5.