(i) X={1,3,4},Y={1,2,3}
X∩Y={1,3}
(ii) A={a,e,i,o,u},B={a,b,c}
A∩B={a}
(iii)A={x:x is a natural number and multiple of 3}={3,6,9....}
B={x:x is a natural number less than 6}={1,2,3,4,5}
∴A∩B={3}
(iv) A={x:x is a natural number and 1<x≤6}={2,3,4,5,6}
B={x:x is a natural number and 6<x<10}={7,8,9}
A∩B=ϕ
(v) A={1,2,3},B=ϕ
A∩B=ϕ