The given function is f( x )=2 x 2 −3x.
Differentiate the function with respect to x.
f ′ ( x )=4x−3
Substitute f ′ ( x ) = 0 to obtain the point of maxima or minima.
f ′ ( x )=0 4x−3=0 x= 3 4
Now, the point 3 4 divides the real line in two different intervals given by,
(a)
In the interval ( −∞, 3 4 ),
f ′ ( x )<0 4x−3<0
Thus, f( x ) is strictly decreasing in the interval ( −∞, 3 4 ).
(b)
In the interval ( 3 4 ,∞ ),
f ′ ( x )>0 4x−3>0
Thus, f( x ) is strictly increasing in the interval ( 3 4 ,∞ ).