Find the intervals in which the function f(x)=3x4−4x3−12x2+5 is (a) strictly increasing (b) strictly decreasing.
Open in App
Solution
f(x)=3x4−4x3−12x2+5 f′(x)=12x3−12x2−24x=12x(x2−x−2) f′(x)=12x(x−2)(x+1) Put f′(x)=0⇒x=0,−1,2 Intervals are (−∞,−1),(−1,0),(0,2),(2,∞) as shown in the table. f(x) is strictly increasing in (−1,0)&(2,∞), and f(x) is strictly decreasing in (−∞,−1)∪(0,2).