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Question

Find the intervals in which the function f(x)=3x44x312x2+5 is
(a) strictly increasing
(b) strictly decreasing.

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Solution

f(x)=3x44x312x2+5
f(x)=12x312x224x=12x(x2x2)
f(x)=12x(x2)(x+1)
Put f(x)=0x=0,1,2
Intervals are (,1),(1,0),(0,2),(2,) as shown in the table.
f(x) is strictly increasing in (1,0)&(2,), and
f(x) is strictly decreasing in (,1)(0,2).
562361_505121_ans.png

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