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Question

Find the intervals in which x2+2x5 is strictly increasing or strictly decreasing.

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Solution

f(x)=x2+2x5
f(x)=2x+2=2(x+1)
Put f(x)=0
x+1=0
x=1
Point x=1 divide the real line in to 2 disjoint intervals.
(,1) and (1,)
when the value of x<1 then x(,1) and f is strictly decreasing.
And when the value of x>1 then x(1,) and f is strictly increasing.
f is strictly decreasing in (,1) and is strictly increasing in (1,)

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