Question

Find the inverse if $f:R\to R_1,f\left(x\right)=\frac{2x+1}{3}$

Answer 1

$f:R\to R,$ $f\left(x\right)=\frac{2x+1}{3}$

$y=\frac{2x+1}{3}$

$3y-1=2x$

$x=\frac{3y-1}{2}$

$f\left(x\right)=\frac{3y-1}{2}$

$f^{-1}\left(x\right)=\frac{3x-1}{2}$