Find the inverse of the given matrix
[2−243]
Let A=[2−243], we have, |A|[2−243]=6−(−8)=14
Cofactors of A are A11=3,=−4,A21=2,A22=2
∴ adj(A)=[3−422]T=[32−42]
Now, A−1=1|A|(adj A)=114[32−42]=⎡⎣314214−414214⎤⎦=⎡⎣31417−2717⎤⎦
Note If determinant of any matrix is zero, then its inverse does not exist.