Find the inverse of the logarithmic function $f$ .
$f (x) = ln (x)$

e^{x}

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- e^{x}

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e^{2 x}

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- e^{2 x}

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Solution

The correct option is A $e^{x}$
Let $y = f (x) = ln (x)$ and now solve for $x$ to find the inverse of the given function.
$y = ln (x)$
$x = e^{y}$
Therefore, the inverse of the function in terms of $x$ is $e^{x}$ .

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Similar questions

Let I $= \int \frac{e^{x}}{e^{4 x} + e^{2 x} + 1} d x . J = \int \frac{e^{- x}}{e^{- 4 x} + e^{- 2 x} + 1} d x,$ Then, for an arbitrary constant c, the value of J-I equals

f (x) = \frac{ln (x^{2} + e^{x})}{ln (x^{4} + e^{2 x})}

. Then

lim x \to \infty f (x)

is equal to

Q. If

f (x) = \frac{ln (x^{2} + e^{x})}{ln (x^{4} + e^{2 x})},

then

lim x \to \infty f (x)

is equal to

\int \frac{e^{x}}{e^{2 x} - 1} d x =

_____

+ c

\int \frac{e^{x}}{e^{2 x} + 5 e^{x} + 6} d x =

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Find the inverse of the logarithmic function f.f(x)=ln(x)

The correct option is A exLet y=f(x)=ln(x) and now solve for x to find the inverse of the given function.y=ln(x)x=eyTherefore, the inverse of the function in terms of x is ex.

Find the inverse of the logarithmic function $f$ .
$f (x) = ln (x)$

The correct option is A $e^{x}$
Let $y = f (x) = ln (x)$ and now solve for $x$ to find the inverse of the given function.
$y = ln (x)$
$x = e^{y}$
Therefore, the inverse of the function in terms of $x$ is $e^{x}$ .