Find the joint equation of the line.
$x - y = 0$ and $x + y = 0$ .

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Solution

$x - y = 0, x + y = 0 \Rightarrow (x - y) (x + y) = 0 \Rightarrow x^{2} + x y - x y + y^{2} = 0 x^{2} - y^{2} = 0 T h i s t w o d e g r e e e q u a t i o n i s p a i r o f s t r a i g h t l i n e$

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Similar questions

Q. Find the joint equation of the following pair of lines :

2 x + y = 0 and 3 x - 5 y = 0

Q. Assertion (A): The joint equation of lines

y = x

and

y = - x

y^{2} = - x^{2}

i.e.

x^{2} + y^{2} = 0.

Reason (R):The joint equation of lines

a x + b y = 0

and

c x + d y = 0.

(a x + b y) (c x + d y) = 0

where

a, b, c, d

are constants.

If the pairs of lines $x^{2} + 2 x y + a y^{2} = 0$ and $a x^{2} + 2 x y + y^{2} = 0$ have exactly one line in common then the joint equation of the other two lines is given by

Q. Find the joint equation of bisectors of the angles between the lines represented by

5 x^{2} + 6 x y - y^{2} = 0

Q. Find the joint equation of lines passing through the origin, each of which making angle of measure

150^{o}

with the line

x - y = 0

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Find the joint equation of the line.x−y=0 and x+y=0.

x−y=0,x+y=0⇒(x−y)(x+y)=0⇒x2+xy−xy+y2=0x2−y2=0Thistwodegreeequationispairofstraightline

Find the joint equation of the line.
$x - y = 0$ and $x + y = 0$ .

$x - y = 0, x + y = 0 \Rightarrow (x - y) (x + y) = 0 \Rightarrow x^{2} + x y - x y + y^{2} = 0 x^{2} - y^{2} = 0 T h i s t w o d e g r e e e q u a t i o n i s p a i r o f s t r a i g h t l i n e$