Find the L.C.M. and H.C.F. of 2x2−6x,x2+9−6xandx2−x−6
A
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B
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C
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D
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Solution
The correct option is D To find the L.C.M. and H.C.F., we need to first resolve each expression into factors. 2x2−6x=2x(x−3)x2+9−6x=x2−2×x×3+32 =(x−3)2 x2−x−6=x2−3x+2x−6 =x(x−3)+2(x−3) =(x−3)(x+2) L.C.M.=2x(x−3)2(x+2) H.C.F.=(x−3)