Question

Find the L.C.M and H.C.F of $\frac{2}{3}$, $\frac{10}{27}$.

• A. L.C.M is $\frac{10}{3}$ and H.C.F is $\frac{2}{27}$
• B. H.C.F is $\frac{10}{3}$ and L.C.M is $\frac{2}{27}$
• C. L.C.M is $\frac{1}{3}$ and H.C.F is $\frac{2}{27}$
• D. L.C.M is $\frac{1}{30}$ and H.C.F is $\frac{21}{27}$

Answer 1

The correct option is A

L.C.M is $\frac{10}{3}$ and H.C.F is $\frac{2}{27}$

L.C.M of fractions = $\frac{L.C.MofthenumbersintheNumerator}{H.C.FofthenumbersintheDenominator}$

= $\frac{L.C.Mof2,10}{H.C.Fof3,27}$

= $\frac{10}{3}$

H.C.F of fractions = $\frac{H.C.FofthenumbersintheNumerator}{L.C.MofthenumbersintheDenominator}$

= $\frac{H.C.Fof2,10}{L.C.Mof3,27}$

= $\frac{2}{27}$