Question

Find the L.C.M of $\frac{2}{7},\frac{3}{14},\frac{5}{3}$

Answer 1

L.C.M of fractions$=\frac{L.C.Mofnumerators}{H.C.Fofdenominators}$

L.C.M of $(\frac{2}{7},\frac{3}{14},\frac{5}{3})=\frac{L.C.Mof(2,3,5)}{H.C.Fof(7,14,3)}$

L.C.M of $2,3,5$

Factors of $2=2\times 1$

Factors of $3=3\times 1$

Factors of $5=5\times 1$

L.C.M$=2\times 3\times 5=30$

H.C.F of $7,14,3$

Factors of $7=7\times 1$

Factors of $14=7\times 2$

Factors of $3=3\times 1$

H.C.F $=1$

L.C.M of $(\frac{2}{7},\frac{3}{14},\frac{5}{3})$ $=\frac{30}{1}=30$