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Question
FIND THE LARGEST 4 DIGIT NUMBER WHICH WHEN DIVIDED BY 4,7AN 13 LEAVES A REMAINDER OF 3 IN EACH CASE
FIND THE LARGEST 4 DIGIT NUMBER WHICH WHEN DIVIDED BY 4,7AN 13 LEAVES A REMAINDER OF 3 IN EACH CASE
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Solution
- To solve these kind of question always remember this formula required number=
n*(L.C.M. of a,b,c)+3 where n is a natural number,in this case n*(L.C.M. of 4,7, 13 )+3=n*364+3 now take n in such a way that this multiplication (n*364) should be closer to 9996,now you will wonder why 9996 let me explain 9996 because you have to add 3 more to 9996 so it will become 9999,but in our case that number is very less as compared to 9996 because if you will take n as 27 then (27*364) will become 9828,there is no point of getting 9996...anyway required number will be 9828+3=9831
- To solve these kind of question always remember this formula required number=
n*(L.C.M. of a,b,c)+3 where n is a natural number,in this case n*(L.C.M. of 4,7, 13 )+3=n*364+3 now take n in such a way that this multiplication (n*364) should be closer to 9996,now you will wonder why 9996 let me explain 9996 because you have to add 3 more to 9996 so it will become 9999,but in our case that number is very less as compared to 9996 because if you will take n as 27 then (27*364) will become 9828,there is no point of getting 9996...anyway required number will be 9828+3=9831
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