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Question

Find the largest number dividing 110,62,92 and leaving the remainder 5,6 and 1 respectively.

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Solution

1105=105
626=56
921=91
105=7×3×5
56=2×2×2×7
91=13×7
gcf of (105, 56, 91) = 7
so the Answer is 7.


1169050_1248324_ans_eca9ef73290d43cdb29a610d9af00cf9.jpg

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