Question

Find the largest number of four digits exactly divisible by 12, 15, 18 and 27.

• A. 5678
• B. 2784
• C. 2793
• D. 9720

Answer 1

The correct option is D 9720

The largest number of four digits is $9999$.
Required number must be divisible by L.C.M of $12,15,18,27$ i.e., $540$.
On dividing $9999$ by $540$, we get $279$ as remainder.
$\therefore$ Required number$=(9999-279)=9720$.