wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the largest number that will divide 1630,525 and 1280 leaving the remainder 6,3 and 4 respectively:

A
29
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
58
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
116
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Can't be determined
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 58
Let us first subtract the remainders from the given numbers as follows:

16306=1624

5253=522

12804=1276

Now, let us factorize 1624,522 and 1276 as shown below:

1624=2×2×2×7×29522=2×3×3×291276=2×2×11×29

We know that the largest positive integer which divides two or more integers without any remainder is called Highest Common Factor (HCF).

Therefore, the HCF of 1624,522 and 1276 is:

HCF=2×29=58

Hence, the largest number is 58.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
GCD Long Division
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon