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Question

Find the largest number which divides 615 and 963 leaving remainder 6 in each case.

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Solution

we have to find the largest number which divide 615 and 963 leaving remainder 6 in each case.

so let us subtract 6 from 615 and 963

6156=609

9636=957

now lets find the HCF

prime factorisation of 609=29×3×3

prime factorisation of 957=29×3×11

now lets take out the common factors from both the cases

29 and 3

x=29×3=87

87 is the number which will divide 615 and 963 leaving remainder 6 in each case.



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