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Byju's Answer
Standard VI
Mathematics
Composite Numbers
Find the larg...
Question
Find the largest number which on dividing 1251, 9377 and 15628 leaves remainders 1, 2 and 3 respectively.
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Solution
Dear student,
n
u
m
b
e
r
s
1251
,
9377
a
n
d
15628
l
e
a
v
e
r
e
m
a
i
n
d
e
r
1
,
2
a
n
d
3
r
e
s
p
e
c
t
i
v
e
l
y
.
s
u
b
t
r
a
c
t
i
n
g
t
h
e
r
e
m
a
i
n
d
e
r
s
f
r
o
m
t
h
e
n
u
m
b
e
r
s
i
t
s
e
l
f
,
i
.
e
.
1251
-
1
=
1250
9377
-
2
=
9375
15628
-
3
=
15625
T
h
e
l
a
r
g
e
s
t
n
u
m
b
e
r
f
o
r
t
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g
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n
c
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n
d
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o
n
w
i
l
l
b
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f
o
u
n
d
b
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f
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d
i
n
g
H
C
F
o
f
t
h
e
n
u
m
b
e
r
s
1250
,
9375
a
n
d
15625
P
r
i
m
e
f
a
c
t
o
r
i
sin
g
t
h
e
n
u
m
b
e
r
s
1250
=
2
×
5
×
5
×
5
×
5
=
2
×
5
4
9375
=
3
×
5
×
5
×
5
×
5
×
5
=
3
×
5
5
15625
=
5
×
5
×
5
×
5
×
5
×
5
=
5
6
H
C
F
=
5
4
=
625
T
h
e
r
e
f
o
r
625
i
s
t
h
e
l
a
r
g
e
s
t
n
u
m
b
e
r
w
h
i
c
h
o
n
d
i
v
i
d
i
n
g
1251
,
9377
a
n
d
15628
w
i
l
l
l
e
a
v
e
r
e
m
a
i
n
d
e
r
1
,
2
a
n
d
3
r
e
s
p
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c
t
i
v
e
l
y
.
Regards
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