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Question

Find the largest positive integer that will divide 122
150 and 115 leaving remainders 5,7 and 11 respectively

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Solution

122 - 5 = 117
150 - 7 = 143
115 - 11 = 104

The HCF of 104, 117 and 143 is 13

The largest number which divides 122, 150 and 115 leaving 5, 7 and 11 respectively as remainders is 13

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