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Question
Find the largest positive integer that will divide 122
150 and 115 leaving remainders 5,7 and 11 respectively
150 and 115 leaving remainders 5,7 and 11 respectively
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Solution
122 - 5 = 117
150 - 7 = 143
115 - 11 = 104
The HCF of 104, 117 and 143 is 13
The largest number which divides 122, 150 and 115 leaving 5, 7 and 11 respectively as remainders is 13
150 - 7 = 143
115 - 11 = 104
The HCF of 104, 117 and 143 is 13
The largest number which divides 122, 150 and 115 leaving 5, 7 and 11 respectively as remainders is 13
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