Question

Find the last two digits of $(148{)}^{1084}$

• A. 6
• B. 66
• C. 56
• D. 16

Answer 1

The correct option is D 16

$(148{)}^{1084}=(37{)}^{1084}\times (4{)}^{1084}$

$=({37}^4{)}^{271}\times (2{)}^{2168}$

$=({37}^2\times {37}^2{)}^{271}\times ....56$

$=(..69\times ..69{)}^{271}\times .....56$

$=(61{)}^{271}\times ....56=....61\times ....56=......16$