Question

Find the last two digits of ${51}^{456}\times {61}^{567}$

Answer 1

The last two digits of ${51}^{456}$ will be $01$ and the last two digits of ${61}^{567}$ will be $21$.
Therefore, the last two digits of ${51}^{456}\times {61}^{567}$ will be the last two digits of $01\times 21=21$.