Find the lateral surface area of cube, if its diagonal is $\sqrt{6} c m .$

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Solution

Let the edge odf the cube be $a ㎝$
length of the diagonal is $\sqrt{3} a = \sqrt{6} \Rightarrow a = \sqrt{2} ㎝$
lateral surface area of the cube is $4 a^{2} = 4 \times {(\sqrt{2})}^{2} = 4 \times 2 = 8 ㎤$

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Find the lateral surface area of cube, if its diagonal is √6cm.

Let the edge odf the cube be a㎝length of the diagonal is √3a=√6⇒a=√2㎝lateral surface area of the cube is 4a2=4×(√2)2=4×2=8㎤

Find the lateral surface area of cube, if its diagonal is $\sqrt{6} c m .$

Let the edge odf the cube be $a ㎝$
length of the diagonal is $\sqrt{3} a = \sqrt{6} \Rightarrow a = \sqrt{2} ㎝$
lateral surface area of the cube is $4 a^{2} = 4 \times {(\sqrt{2})}^{2} = 4 \times 2 = 8 ㎤$