Find the LCM and HCF of 26- 91 and verify that LCM - HCF - product of the two numbers-

26 = 2 × 13 91 =7 × 13 HCF = 13 LCM = 2 × nbsp;7 × nbsp;13 =182 Product of two numbers = 26 × 91 = 2366 Product of HCF and LCM = 13 × 182 = 2366 Hence, prod ...

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Standard IX

Mathematics

Product of Two Numbers = HCF x LCM

Find the LCM ...

Question

Find the LCM and HCF of 26, 91 and verify that LCM $\times$ HCF = product of the two numbers.

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Solution

26 = 2 $\times$ 13
91 =7 $\times$ 13
HCF = 13
LCM = $2 \times 7 \times 13 = 182$
Product of two numbers $= 26 \times 91 = 2366$
Product of HCF and LCM $= 13 \times 182 = 2366$
Hence, product of two numbers = $H C F \times L C M$

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Find the LCM and HCF of 26, 91 and verify that LCM × HCF = product of the two numbers.

26 = 2 × 13 91 =7 × 13 HCF = 13 LCM = 2×7×13=182 Product of two numbers =26×91=2366 Product of HCF and LCM =13×182=2366 Hence, product of two numbers = HCF×LCM

Find the LCM and HCF of 26, 91 and verify that LCM $\times$ HCF = product of the two numbers.

26 = 2 $\times$ 13
91 =7 $\times$ 13
HCF = 13
LCM = $2 \times 7 \times 13 = 182$
Product of two numbers $= 26 \times 91 = 2366$
Product of HCF and LCM $= 13 \times 182 = 2366$
Hence, product of two numbers = $H C F \times L C M$