Question

Find the $LCM$ and $HCF$ of $\frac{1}{2},\frac{3}{4}$ and $\frac{7}{6}$.

• A. $HCF=\frac{1}{12},LCM=\frac{21}{2}$
• B. $HCF=\frac{1}{15},LCM=\frac{23}{2}$
• C. $HCF=\frac{23}{2},LCM=\frac{1}{15}$
• D. $HCF=\frac{21}{2},LCM=\frac{1}{12}$

Answer 1

The correct option is A $HCF=\frac{1}{12},LCM=\frac{21}{2}$

For eg fraction are $\frac{1}{2},\frac{3}{4}$ and $\frac{7}{6}$

$1)$ If we want these $L.C.M$

$L.C.M=(\frac{1}{2},\frac{3}{4},\frac{7}{6})$

$=\frac{L.C.M(1,3,7)}{H.C.F(2,4,6)}$

$\frac{21}{2}$

$2)$ If we want these $H.C.F$

$H.C.F(\frac{1}{2},\frac{3}{4},\frac{7}{6})$

$\frac{H.C.F(13,7)}{L.C.M(2,4,6)}$

$=\frac{1}{12}$