Question

Find the LCM and HCF of the following pairs of integers and verify in each case that $LCM\times HCF=Productsoftwonumbers$:$26and91$.

Answer 1

Step 1: Finding the LCM and HCF:

Definition:

1. LCM means the smallest common multiple of two or more numbers

2. HCF means the highest common factors of two or more numbers.

Given numbers are $26and91$.

Factorization of $26and91$:

Factorizing $26$we get $26=2\times 13$.

Factorizing $91$we get $91=7\times 13$.

Finding LCM and HCF:

Here the HCF = $13$.

LCM = $2\times 7\times 13=182$.

Step 2: Verifying $LCM\times HCF=Productoftwonumbers$:

Here, $LCM\times HCF=13\times 182=2366$.

and product of the given numbers= $26\times 91=2366$.

Hence, $LCM\times HCF=Productofthegivennumbers$.