Question

Find the LCM and HCF of the following pairs of integers and verify that $LCM\times HCF=Productofthenumbers$

$29260and1482$

Answer 1

Finding LCM and HCF:

HCF and LCM:

• The full form of H.C.F. is the greatest common factor between given two or more numbers.
• The full form of L.C.M. is the least common multiple that is exactly divisible by two or more numbers.

Given data:

Given numbers are $29260and1482$

Factorization of $29260and1482$

Factorizing, $29260=2\times 2\times 5\times 7\times 11\times 19$$=2^2\times 5\times 7\times 11\times 19$

Factorizing, $1482=2\times 3\times 13\times 19$

Here the HCF or the highest common factor is $=2\times 19=38$

The L.C.M or the least common multiple=$=2\times 2\times 3\times 5\times 7\times 11\times 13\times 19=1141140$

Verification:

Here,$LCM\times HCF=38\times 1141140=43363320$

Product of the numbers $29260\times 1482=43363320$

Hence, $LCM\times HCF=38\times 1141140=43363320$

Hence, $LCM\times HCF=Productofthetwonumbers$ (verified)