Find the lcm of 40- 42- 45 - Maths Q-A

Solve for LCM of given numbersThe prime factors are given as,40=(2 × 2 × 2 × 5) = 2^3×5^1.42= (2 × 3 × 7) = 2^1×3^1×7^1.45= (3 × 3 × 5) = 3^2×5^1 L ...

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Standard VI

Mathematics

Prime and Composite Numbers

Find the lcm ...

Question

Find the LCM of $40, 42, 45 .$

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Solution

Solve for LCM of given numbers
The prime factors are given as,
$40 = (2 \times 2 \times 2 \times 5) = 2^{3} \times 5^{1} .$
$42 = (2 \times 3 \times 7)$ $= 2^{1} \times 3^{1} \times 7^{1} .$
$45 = (3 \times 3 \times 5)$ $= 3^{2} \times 5^{1}$
LCM of $40, 42,$ and $45$ can be determined by multiplying prime factors raised to their respective highest power,
$\Rightarrow 2^{3} \times 3^{2} \times 5 \times 7 = 2520 .$
The LCM of $40, 42,$ and $45$ by prime factorization is $2520 .$
Hence, the LCM of the given terms $40, 42,$ and $45$ is $2520$

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Find the LCM of 40,42,45.

Find the LCM of $40, 42, 45 .$