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Question

Find the LCM of 5(y2z2),y2+2yz+z2

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Solution

We know that LCM is the least common multiple.

Factorise 5(y2z2) as follows:

5(y2z2)=5(yz)(y+z) (using identity a2b2=(a+b)(ab))

Now, factorise y2+2yz+z2 as follows:

y2+2yz+z2=(y+z)2 (using identity (a+b)2=a2+b2+2ab)

Since the least common multiple between the polynomials 5(y2z2)and y2+2yz+z2 is 5(yz)(y+z)2.

Hence, the LCM is 5(yz)(y+z)2.

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