wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the LCM of polynomials p(x)=x31, q(x)=x3+1 and r(x)=(x2+1)2x2.

Open in App
Solution

We observe p(x)=x31=x313. Factoring using a3b3=(ab)(a2+ab+b2), we get p(x)=(x1)(x2+x+1)
Similarly, q(x)=x3+1=x3+13=(x+1)(x2x+1); we have used a3+b3=(a+b)(a2ab+b2).
Finally r(x)=(x2+1)2x2=(x2+x+1)(x2x+1).
irreducible factors of p(x) or q(x)Highest exponent
Algebraic (x+1)1
Algebraic (x1)1
Algebraic (x2x+1)1
Algebraic (x2+x+1)1
Hence the LCM
(x+1)(x1)(x2+x+1)(x2x1)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Lowest Common Multiple
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon