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Question

Find the LCM of the following: a2bc,b2ac,c2ab

A
a2b2c2
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B
a2b3c2
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C
a3b2c2
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D
None of these
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Solution

The correct option is A a2b2c2
We know that the least common multiple (LCM) is the smallest number or expression that is a common multiple of two or more numbers or algebraic terms.

We first factorize the given monomials a2bc,b2ac and c2ab as shown below:

a2bc=a×a×b×cb2ac=b×b×a×cc2ab=c×c×a×b

Now multiply all the factors, using each common factor only once, therefore, the LCM is:

a×a×b×b×c×c=a2b2c2

Hence, the LCM of a2bc,b2ac and c2ab is a2b2c2.

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