Find the LCM of the following. (i) 90,150,225 (ii) 35a2c3b,42a3cb2,30ac2b3 (iii) (a−1)5(a+3)2,(a−2)2(a−1)3(a+3)4 (iv) x3+y3,x3−y3,x4+x2y2+y4
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Solution
(i) Now, 90=2×3×3×5=21×32×51 150=2×3×5×5=21×31×51 225=3×3×5×5=32×52 The product 21×32×52=450 is the required LCM.
(ii) Now, LCM of 35, 42 and 30 is 5×7×=210 Hence, the required LCM =210×a3×c3×b3=210a3c3b3
(iii) Now, LCM of (a−1)5(a+3)2,(a−2)2(a−1)3(a+3)4 is (a−1)5(a+3)4(a−2)2
(iv) Let us first find the factors for each of the given expressions. x3+y3=(x+y)(x2−xy+y2) x3−y3=(x−y)(x2+xy+y2) x4+x2y2+y4=(x2+y2)−x2y2(x2+xy+y2)(x2−xy+y2) Thus, (x+y)(x2−xy+y2)(x−y)(x2+xy+y2) =(x3+y3)(x3−y3)=x6−y6