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Question

Find the LCM of the following.
(i) 90,150,225
(ii) 35a2c3b,42a3cb2,30ac2b3
(iii) (a1)5(a+3)2,(a2)2(a1)3(a+3)4
(iv) x3+y3,x3y3,x4+x2y2+y4

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Solution

(i) Now, 90=2×3×3×5=21×32×51
150=2×3×5×5=21×31×51
225=3×3×5×5=32×52
The product 21×32×52=450 is the required LCM.

(ii)
Now, LCM of 35, 42 and 30 is 5×7×=210
Hence, the required LCM =210×a3×c3×b3=210a3c3b3

(iii) Now, LCM of (a1)5(a+3)2,(a2)2(a1)3(a+3)4 is (a1)5(a+3)4(a2)2

(iv)
Let us first find the factors for each of the given expressions.
x3+y3=(x+y)(x2xy+y2)
x3y3=(xy)(x2+xy+y2)
x4+x2y2+y4=(x2+y2)x2y2(x2+xy+y2)(x2xy+y2)
Thus, (x+y)(x2xy+y2)(xy)(x2+xy+y2)
=(x3+y3)(x3y3)=x6y6

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