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Question

Find the LCM of the polynomials 8x2128 and 2x216x+32.

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Solution

We have
p(x)=8x2128=8(x216)=8(x242)=23(x+4)(x4);
q(x)=2x216x+32=2(x28x+16)=2(x22(x)(4)+42)=2(x4)2.
We observe
irreducible factors of p(x) or q(x)Highest exponent
Numeric 23
Algebraic (x+4)1
Algebraic (x4)2
Hence the LCM is 23(x+4)(x4)2=8(x+4)(x4)2.

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