Find the least count of a vernier caliper whose 50 vernier scale divisions match with 49 main scale divisions?

Given: least count of main scale is 1 mm.

0.1 mm

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0.02 mm

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0.05 mm

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0.001 mm

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Solution

The correct option is B
0.02 mm

Since 50 vernier scale divisions match with 49 main scale divisions, vernier scale division is:
$1 V S D = \frac{49 \times 1 m m}{50}$

Using the formula for least count,
$L C = 1 M S D - 1 V S D$
$L C = 1 m m - \frac{49}{50} m m$
$L C = 0.02 m m$

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Similar questions

Find the least count of a vernier caliper whose 50 vernier scale divisions match with 49 main scale divisions?

Given: least count of main scale is 1 mm.

Find the least count of a vernier caliper whose 50 vernier scale divisions match with 49 main scale divisions?

Given: least count of main scale is 1 mm.

A Vernier caliper has 1 mm marks on the main scale. It has 20 equal divisions on the Vernier scale which matches with 16 main scale divisions. For this Vernier caliper, the least count is:

Q. A vernier caliper has 1 mm marks on the math scale. It has 20 equal divisions on the vernier scale (VSD) which match with 18 main scale divisions (MSD). What is the least count (L.C) for this vernier caliper?

(A) 0.1 mm
(B) 0.01 mm
(C) 0.2 mm
(D) 0.02 mm

50

divisions on the vernier scale coincides with

49

divisions on the main scale of a vernier caliper. The least count of instrument, if graduation on the main scale is

2 m m

, is :

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Find the least count of a vernier caliper whose 50 vernier scale divisions match with 49 main scale divisions? Given: least count of main scale is 1 mm.

The correct option is B 0.02 mm Since 50 vernier scale divisions match with 49 main scale divisions, vernier scale division is: 1 VSD=49×1 mm50 Using the formula for least count, LC=1 MSD−1 VSD LC=1 mm−4950 mm LC=0.02 mm

Find the least count of a vernier caliper whose 50 vernier scale divisions match with 49 main scale divisions?

Given: least count of main scale is 1 mm.

The correct option is B
0.02 mm

Since 50 vernier scale divisions match with 49 main scale divisions, vernier scale division is:
$1 V S D = \frac{49 \times 1 m m}{50}$

Using the formula for least count,
$L C = 1 M S D - 1 V S D$
$L C = 1 m m - \frac{49}{50} m m$
$L C = 0.02 m m$