Question

Find the least fraction, which must be multiplied to $(1\frac{2}{4}-\frac{1}{2}+3\frac{6}{16}-\frac{1}{16}+\frac{2}{8})$to make it an integer.

• A. $\frac{24}{1}$
• B. $\frac{16}{1}$
• C. $\frac{73}{1}$
• D. $\frac{1}{73}$

Answer 1

The correct option is B $\frac{16}{1}$

$1\frac{2}{4}-\frac{1}{2}+3\frac{6}{16}-\frac{1}{16}+\frac{2}{8}$

=$\frac{6}{4}-\frac{1}{2}+\frac{54}{16}-\frac{1}{16}+\frac{2}{8}$

Taking LCM of denominators and solving,

$\frac{24-8+54-1+4}{16}$=$\frac{73}{16}$

Now, if we multiply $\frac{73}{16}$ by $\frac{16}{1}$, it becomes 73, which is an integer

Hence, $\frac{16}{1}$ is the required fraction.