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Question

Find the least integral positive value of x which satisfied the inequality x2+16x+64>20.

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Solution

x2+16x+640
(x+8)20
xϵR
x2+16x+64>20
Squarring both sides
x2+16x+64>400
x2+16x336>0
(x+28)(x12)>0
xϵ(,28)(12,)
So, least positive integral value =13

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